1. The problem statement, all variables and given/known data explain in terms of linear approximations why the approximation is reasonable. (1.01)^6=1.06 2. Relevant equations y-y1=m(x-x1) L(x)=f(a) + f'(a)(x-a) 3. The attempt at a solution given 1.01^6, f(x)=x^6, so f'(x)=6x^5 plugging in x=1, f'(1)=6 y-6=6(x-1) Is that the right equation? Because in class the equation was y-1=6(x-1) y=1.06 which is the correct answer. But why is y1=1 and not 6??? Can anyone catch that?