(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

Find the linear approximation of [itex]\sqrt[3]{27.02}[/itex]

2. Relevant equations

f(x)+f'(x)(x-a)

3. The attempt at a solution

So what I did was work with[itex]\sqrt[3]{27}[/itex] since that's an easily known value. So my f(x)=x[itex]^{1/3}[/itex] and my f'(x)=1/3x[itex]^{-2/3}[/itex]. From there, I worked f(27) = 3, and f'(27)=1/27.

Then I used the above equation. 3+1/27(x-27). For my value of x, I used 27.02, and got .0004.

Something tells me I'm doing something incorrectly, though...

Thanks for the help!

**Physics Forums | Science Articles, Homework Help, Discussion**

Dismiss Notice

Join Physics Forums Today!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

# Homework Help: Linear Approximations

**Physics Forums | Science Articles, Homework Help, Discussion**