(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

Find the linear approximation of [itex]\sqrt[3]{27.02}[/itex]

2. Relevant equations

f(x)+f'(x)(x-a)

3. The attempt at a solution

So what I did was work with[itex]\sqrt[3]{27}[/itex] since that's an easily known value. So my f(x)=x[itex]^{1/3}[/itex] and my f'(x)=1/3x[itex]^{-2/3}[/itex]. From there, I worked f(27) = 3, and f'(27)=1/27.

Then I used the above equation. 3+1/27(x-27). For my value of x, I used 27.02, and got .0004.

Something tells me I'm doing something incorrectly, though...

Thanks for the help!

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# Linear Approximations

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