- #1

nateshoe

- 9

- 0

y'=4x–y+4; y(0)=8

2. The attempt at a solution[/b]

This is simply a first-order DE

So:

y'+y=4x+4

P(x)=1

Q(x)=4x+4

p(x)=e^x

So that ends up being:

ye^x=(4xe^x+4e^x)dx

Integration:

ye^x=4xe^x-4e^x+4e^x

ye^x=4xe^x

divide by e^x

y=4x+C

y=4x+8

However it tells me I'm wrong. either I'm very stupid or I'm going about this completely wrong.

Thanks,

Nate