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I am trying to work out the following:

cos

^{2}(t)sin(t)y' = -cos

^{3}(t)y + 1

I've moved put the equation into the standard form and determined that my integrating factor is the integral of cos(t)/sin(t) or the integral of cot(t). This gives me e

^{lnsinu +c}or sin(t).

I multiple both sides and simplify and I get to this point"

y*sin(t) = Integral of: 1/cos

^{2}(t) and I'm having a hard time finding the integral of this function.

Once I solve the integral on the right hand side I'm home free but can't figure it out.

Any help is appreciated.

Thanks

Ryan