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**1. Homework Statement**

I'm told that this is a linear equation

[tex]y' = \frac{4ln|x| - 2x^2y}{x^3}[/tex]

**2. The attempt at a solution**

[tex]x^3 = (4ln|x|-2x^2y)\frac{dx}{dy}[/tex]

giving:

[tex]P = 4ln|x|-2x^2[/tex]

[tex]Q = x^3[/tex]

[tex]\int Pdx = 4x-\frac{2x^3}{3}[/tex]

[tex]e^\int^p^d^x = e^4^x^-^\frac^{2x^3}^{3}[/tex]

[tex]ye^\int^p^d^x = \int e^4^x^-^\frac^{2x^3}^{3} x^3[/tex]

I know this is too complicated and ugly.. It has to be wrong so far...

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