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lew0049

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Q

uestion: A rod made from a particular alloy is heated from 27.5 °C to 127 °C. Its length increases by 9.13 x 10-4 m. The rod is then cooled from 27.5 °C to 4.19 °C. By how much does the rod shrink?

After breaking down the basic thermal expansion equation I get: (9.13E-4 / 99.5)* (23.31) = change of L = 2.14E-4 m ... am I missing something because this doesn't seem too complicated