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Linear Expansion

  1. Jan 26, 2006 #1
    An iron rod has a diameter of 2.50cm at 20.0°. To what temperature must it be heated to fit into a ring with an inside diameter of 2.51cm. I'm given: alpha=1.0x10^-5

    I'm not sure how to apply it to the △L=(alpha)(object length)△T
     
  2. jcsd
  3. Jan 26, 2006 #2
    Since the diameter is one dimensional quantity, L=2.50cm.
    It seems a little bit strange but the diameter will expand just like a iron rod.
     
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