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Linear momentum and collisions

  1. Jun 11, 2010 #1
    1. The problem statement, all variables and given/known data

    A 3 kg steel ball strikes a wall with a speed of 10 m/s at an angle of 60° with the surface. It bounces off with the same speed and angle. If the ball is in contact with the wall for 0.2 s, what is the average force exerted by the wall on the ball?

    [PLAIN]http://img708.imageshack.us/img708/5262/15128648.gif [Broken]

    3. The attempt at a solution

    Here is the solution to this problem:

    Now, where did they get the first minus sign from in "-v sin60-vsin60" (in the third line)?? Isn't the ball initially moving towards the positive x direction? :confused:
     
    Last edited by a moderator: May 4, 2017
  2. jcsd
  3. Jun 11, 2010 #2
    i dont see anything wrong.

    vxf = -v sin60 (-ve x)
    vxi = v sin60 (ve x)

    vxf - vxi = -2vsin60
     
  4. Jun 11, 2010 #3

    Doc Al

    User Avatar

    Staff: Mentor

    Yes, the ball is initially moving in the +x direction. But that first minus sign comes from the final velocity along the x-axis. After it bounces off the wall it's moving in the negative direction.
     
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