[SOLVED] linear motion 1. The problem statement, all variables and given/known data A car enters a turn at 85 km/h, slows to 55 km/h, and emerges 28 s later at 35 degrees to its original motion, still moving at 55 km/h. What is the magnitude an direction of the average acceleration measure with respect to the car's original direction? Book gives the answer as 0.5 m/s^2 and 142 degrees. 2. Relevant equations a=(v2-v1)/delta t 3. The attempt at a solution V2x= 55 cos 35 degrees=55(.819)=.45 km/h V1x=80 km/h a= 35 km/h (1000m)/28s(3600s)= 0.35 m/s^2 I have no idea how to arrive at the direction of the acceleration vector.