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Homework Help: Linear motion

  1. Jul 1, 2010 #1
    1. The problem statement, all variables and given/known data

    A particle moves along the positivex-axis .At time t seconds after leaving a fixed point O from rest, the displacement of the particle from O is x cm. The acceleration, a of the particle is defined by

    a=5-3t , 0<=t<=1

    =-(4t+1), t>1

    Find the speed of the particle when x=2.5

    2. Relevant equations

    3. The attempt at a solution

    Integrate twice to get the displacement function,

    x=5t^2/2-t^3/2 , 0<=t<=1

    = -2/3t^3-2t^2 ,t>1

    so 5t^2/2-t^3/2=2.5

    solving this does not give me the answer. Where have i gone wrong?
  2. jcsd
  3. Jul 1, 2010 #2
    ur mistake is u considered only one condition thus u integrated only for 0<=t<=1. How r u sure u that at the time the particle will be at x=2.5 will be less than or equal to 1s. In fact if u do some calculation u will find its not true. thus u have to apply the second condition for t.
  4. Jul 1, 2010 #3
    But even when i considered the other one, i don get the answer too which is 1.5m
  5. Jul 1, 2010 #4
    actually u have to apply both integrating part by part.
  6. Jul 1, 2010 #5
    sorry but i don get what u mean
  7. Jul 7, 2010 #6
    any other insights to this problem?
  8. Jul 7, 2010 #7
    The way I see your work, in the 2nd integration to find x of t>1s, you set the lower limits as x=0 and t=0, right? Have it checked. That's wrong. Remember that you are considering t>1s; t=0 doesn't fit.
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