let be the linear operator: (Hermitian ??)(adsbygoogle = window.adsbygoogle || []).push({});

[tex] L = -i(x\frac{d}{dx}+1/2) [/tex]

then the "eigenfunctions" are [tex] y_{n} (x)=Ax^{i\lambda _{n} -1/2 [/tex]

then my question is how would we get the energies imposing boundary conditions? (for example y(0)=Y(L)=0 wher L is a positive integer )....:rofl: :rofl:

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# Linear operator

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