(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

A solid ball is at the top of a 2 meter inclined plane. Assuming friction is negligible, what is its linear speed (m/s) as it reaches the bottom?

2. Relevant equations

PE=mgh

KE=.5mv^2

RKE=.5Iw^2

I of ball=.4mr^2

w=v/r

3. The attempt at a solution

Pretty much what i did was set PE=KE+RKE

which is mgh=.5mv^2+.5(.4mr^2)+w^2 masses cancel out and so does r when v/r is replaced with w

equation is now gh=.5v^2+.5(.4)v^2

if i solve for v i get: 2v^2=2gh/.4= v^2=gh/.4

thus v=sqrt(9.81*2/.4)

v=7.0 m/s

i really have no idea if im doing this right...

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# Linear Speed

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