Linear Temperature Scale

  • Thread starter jdawg
  • Start date
  • #1
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Homework Statement



I'm not sure what I'm doing wrong on this problem! Please help :)

Suppose that on a linear temperature scale X, water boils at -40.0°X and freezes at -174°X. What is a temperature of 146 K on the X scale? (Approximate water's boiling point as 373 K.)

Homework Equations





The Attempt at a Solution



(K1,X1)=(373, -40)
(K2,X2)=(273, -174)

m=(X2-X1)/(K2-K1)=0.74627 X per K

X-X1=m(K-K1)
X=0.74627K-238.358
X=0.74627(146)-238.358
X= -129.4
 

Answers and Replies

  • #3
367
2
I tried plugging in that slope into the formula and my online homework wouldn't accept the answer I got. Is the slope not X/K?
 
  • #4
367
2
Never mind, I messed up when I entered it into my calculator! Thanks so much!
 

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