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Linear Temperature Scale

  1. Aug 27, 2014 #1
    1. The problem statement, all variables and given/known data

    I'm not sure what I'm doing wrong on this problem! Please help :)

    Suppose that on a linear temperature scale X, water boils at -40.0°X and freezes at -174°X. What is a temperature of 146 K on the X scale? (Approximate water's boiling point as 373 K.)

    2. Relevant equations



    3. The attempt at a solution

    (K1,X1)=(373, -40)
    (K2,X2)=(273, -174)

    m=(X2-X1)/(K2-K1)=0.74627 X per K

    X-X1=m(K-K1)
    X=0.74627K-238.358
    X=0.74627(146)-238.358
    X= -129.4
     
  2. jcsd
  3. Aug 27, 2014 #2
    For m, I get 1.34.

    Chet
     
  4. Aug 27, 2014 #3
    I tried plugging in that slope into the formula and my online homework wouldn't accept the answer I got. Is the slope not X/K?
     
  5. Aug 27, 2014 #4
    Never mind, I messed up when I entered it into my calculator! Thanks so much!
     
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