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Linearising a cosine curve

  1. Sep 16, 2012 #1
    1. The problem statement, all variables and given/known data

    For my physics EEI, I have developed the formula: g-forces=√(391.88-337.12 cosθ)/9.8

    I need to linearise the graph into the form y=mx+c.

    I'm not sure where just the angle is the independent or cos of the angle.

    2. Relevant equations

    y=k√(x) can be graphed as y vs. √(x) to linearise

    3. The attempt at a solution

    The square root of a negative is undefined, therefore √(cosθ) is unable to be done for all values
     
  2. jcsd
  3. Sep 17, 2012 #2

    SammyS

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    Hello Maluras. Welcome to PF !

    Is (391.88-337.12 cosθ ) ever negative?

    -1 ≤ cos(θ) ≤ 1

    Multiply by -337.12 then add 391.88 .

    What's your conclusion regarding the range of (391.88-337.12 cosθ ) ?
     
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