A reel of mass M and of radius a has tape wound round its axle(adsbygoogle = window.adsbygoogle || []).push({});

which has radius b . The tape has negligible mass. The reel is

initially at rest on a rough horizontal table when the free end of the

tape is pulled horizontally by a constant force T , as shown below.

The pull T is sufficiently small that the reel does not slide.

Show that the resulting acceleration is given by

a=dv/dt = a(a-b)T/M(k^2+a^2)

where V is the velocity of the centre of the reel and k is the radius

of gyration of the reel.

working so far,

dv/dt= r*angular acceleration(al)

dv/dv=t*r/I i=moment of inertia

unable to complete the proof.

please help

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# Homework Help: Linera acceleration

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