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Lines and planes

  1. Nov 6, 2013 #1
    Equation of plane containing points (a,0,0) (0,b,0) (0,0,c)

    Vectors
    <-a,b,0> <-a,0,c>
    Normal vector
    <bc,ac,ab>

    Plane
    Bc(x-a)+ac(y-b)+ab(z-c)=
    Bcx+acy+Abz=3abc
    Book is showing = abc
     
  2. jcsd
  3. Nov 6, 2013 #2

    tiny-tim

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    hi nameVoid! :smile:
    nooo … bc(x-a)+ac(y-b)+ab(z-c) = -2bc :wink:
     
  4. Nov 6, 2013 #3

    haruspex

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    If the point <x, y, z> lies in the plane, what do you have to subtract to get a vector parallel to the plane?
     
  5. Nov 6, 2013 #4

    LCKurtz

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    (a,b,c) is not a point on the plane, but (a,0,0) is. And what should the right side =?
     
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