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Link Budget Antenna: use of effective aperture and the gain in a problem
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[QUOTE="Master1022, post: 6388514, member: 650268"] [B]Homework Statement:[/B] If we have a system where we receive power ## x ## W at the receiver. Find the power at the input if the receiver and transmitting antennae are parabolic and the same size / transmission efficiency. [B]Relevant Equations:[/B] Power density = Power / Area Hi, I was just attempting this problem and was confused about the calculation process involved. [B]Context:[/B] In earlier parts of the question, we calculate the gain ## G ## and effective aperture ## A ## for the parabolic antennae. [B]My Attempt:[/B] We are given the power at the output ## x ## in Watts 1) The receiving antenna has a gain ## G ## and therefore we must divide by that to get the power at the entry to the receiving antenna ## \frac{x}{G} ## 2) Convert the power to power density $$ P_{receiver} = P_r = \frac{x}{G \cdot A} $$ 3) We know that: $$ P_r = \frac{P_t G}{4 \pi R^2} $$ and therefore, we can find $$ P_t = \frac{4 P_r \pi R^2}{G} $$ However, the answer only includes the gain ## G ## once, that is it uses the formula: $$ P_t = \frac{4 x \pi R^2}{G A} $$ I cannot understand why this is the case. I know that the effective aperture and gain related to one another, but I thought the effective aperture was about the effectiveness of the physical antenna and the gain was about the amplification of the signal. Should I not be counting the gain twice? Any help is greatly appreciated [/QUOTE]
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Link Budget Antenna: use of effective aperture and the gain in a problem
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