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Homework Help: Linkage isomer in complexes

  1. Oct 7, 2007 #1
    [SOLVED] Linkage isomer in complexes

    I would like to ask a question on linkage isomer on complexes.
    Say, I have a complex Ru(phen)2(NCS)2.
    NCS can exhibit linkage isomer.
    Suppose I focus on linkage isomerism only, regardless of optical isomer or geometrical isomer.
    Surely, the complex can exist as S-C=N->Ru<-N=C-S and N=C-S->Ru<-S-C=N.
    Can the complex be exist as S-C=N->Ru<-S-C=N.

    p.s.: sorry for my poor representation, = means triple bond and either -> or <- is dative covalent bond.

  2. jcsd
  3. Oct 7, 2007 #2
    Theres 3 isomers in that case isnt there?

    1x N linkage
    1x S linkage
    1x Mixture

    Theres technically four, but since the other "Mixture" isomer is equivalent to the first one chemically, I'd say there was three personally...
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