[Solved] Liquid Density Puzzle 1. The problem statement, all variables and given/known data 3. The attempt at a solution I think there's an assumption here that i'm missing, firstly I worked out how big each cube was by setting up simple simultaneous equations which gave me; Green = 0.21m Red = 0.14m & Blue = 0.28m And also Green + Red + Blue = 20kg. From here i'm stuck, I've thought about putting them all together giving me a volume of; 21^3 * 10^-6 + 14^3 * 10^-6 + 28^3 * 10-^6 =9261 +10^-6 + 2744 *10^-6 + 21952 * 10^-6 = 33957 * 10^-6 = 3.3957 * 10^-2 m³ Giving them all a density of 20 / that, but I'm sure it's a dead end =|, can anyone else see a better way of doing this?/An assumption that i'm missing? thanks alot in advance.