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Liquid flowing in a tube

  1. Apr 15, 2014 #1
    1. The problem statement, all variables and given/known data

    A horizontal tube of uniform cross sectional area 'A' is bent in the form of U. If the liquid of density 'ρ' enters and leaves the tube with velocity 'v' then how much external force is required to hold the bend stationary ?

    2. Relevant equations



    3. The attempt at a solution

    I think the bend in the tube provides centripetal force to the fluid flowing through it .As a result the fluid also exerts force on the bend. But then radius of the curve is not given.

    In 1 sec liquid of mass ρAv is flowing through any cross section of the tube.

    I would be grateful if somebody could help me with the problem.
     
  2. jcsd
  3. Apr 15, 2014 #2

    TSny

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    You can work the problem using centripetal force, but there's an easier way.
    momentum
     
  4. Apr 15, 2014 #3
    The change in momentum/sec 2ρAv2 of the liquid is the force by the tube on the liquid.Same force is applied by liquid on the tube .So external force F = 2ρAv2 needs to be applied , in opposite direction to the force by liquid to keep the tube at rest .

    Is it correct ?
     
    Last edited: Apr 15, 2014
  5. Apr 15, 2014 #4

    TSny

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    Looks good!
     
  6. Apr 15, 2014 #5
    Thanks TSny !

    There is a similar problem in which I am having difficulty .

    Q . Water flows with a velocity v along a rubber tube having the form of a ring. The radius of the ring is R and diameter of the tube is d (d<<R). Find the force with which the rubber tube is stretched.(ρ is the density of water).

    My reasoning : The mass/sec of water flowing through any cross section of the tube is given by ρπd2v/4 .

    Not sure what to do next .
     
  7. Apr 15, 2014 #6

    TSny

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    Can you relate a ring to a U-tube?
     
  8. Apr 15, 2014 #7
    Three similarities I can think

    1) Liquid goes in liquid comes out.
    2) In U tube a part is curved whereas a ring is completely circular.
    3) Change of momentum/sec of liquid is same in both the cases i.e 2ρAv2
     
    Last edited: Apr 15, 2014
  9. Apr 15, 2014 #8

    TSny

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    For what part of the circumference of the ring does this expression apply?
     
  10. Apr 15, 2014 #9
    Approx. 100% of the circumference .Almost a full circle .
     
  11. Apr 15, 2014 #10

    TSny

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    No. Think about where the factor of 2 comes from in 2ρAv2 in the result for the U-tube.
     
  12. Apr 15, 2014 #11
    Factor of 2 comes from a reversal of momentum of the fluid which had entered the curved part.
     
  13. Apr 15, 2014 #12

    TSny

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    Yes. How much of the circumference corresponds to reversal of momentum?
     
  14. Apr 15, 2014 #13
    Can't assign a numeric value ,but a very small fraction of the circumference .
     
  15. Apr 15, 2014 #14

    TSny

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    Consider a cross section of the ring and the direction of momentum flowing through it. How far around the ring do you need to go before you reach a second cross section where the direction of momentum is reversed relative to the first cross section?
     
  16. Apr 15, 2014 #15
    The distance around the ring is ∏R i.e half the circumference.
     
  17. Apr 15, 2014 #16

    TSny

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    OK. Draw a free body diagram for the portion of the rubber tube representing half a circumference. Include the total force due to the motion of the fluid in this section of the tube as well as any other forces acting on this section of the tube.
     
  18. Apr 15, 2014 #17
    In the attachment I have shown the left half of the tube.

    The net force due to the fluid is towards left having magnitude 2ρAv2. Since it is in equilibrium an equal amount of force is exerted by right half of the rubber tube.
     

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  19. Apr 15, 2014 #18

    TSny

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    OK. Can you be more specific about the force exerted by the right half? At what point(s) of the left half does the force of the right half act?
     
  20. Apr 15, 2014 #19
    The force on the left half is exerted on the circumference of two circular end points of the tube (in red). It's exaggerated view is shown towards right . The blue lines indicate the force on the circumference .The right half exerts force through the two end points .
     

    Attached Files:

  21. Apr 15, 2014 #20

    TSny

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    OK. How would you relate the question "Find the force with which the rubber tube is stretched" to the force on a circular cross section (i.e., one of your blue forces in your figure)?
     
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