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Liquid in vat

  1. Sep 17, 2009 #1
    The problem statement, all variables and given/known data
    A 1.60 m-diameter vat of liquid is 2.30 m deep. The pressure at the bottom of the vat is 1.20 atm. What is the mass of the liquid in the vat in Kg?


    The attempt at a solution
    A= pi*r^2 = pi (0.8)^2 = 2.01 m^2

    2.01m^2 x 20.260 kPa = 40.7226

    40.7226 x 9.8 = 399kg

    and i got it wrong :(
     
  2. jcsd
  3. Sep 18, 2009 #2

    Redbelly98

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    You're very close. What is the equation relating mass and weight?

    p.s. Welcome to Physics Forums.
     
  4. Sep 18, 2009 #3

    tiny-tim

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    Hi benedict9999! :smile:
    Force = mass times acceleration,

    so why is your g on the left? :wink:
     
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