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Liquid Mechanics Question

  1. Oct 4, 2004 #1
    If I have a container, filled with water, and a hole is cut in the side at some distance h from the top, how do I go about finding the distance R from the foot of the container that the stream will impact the floor? Do I use Bernouilli's Equation: P1 + ½ pv12 + pgy1 = P2 + ½ pv22 + pgy2 Where P = pressure at depth h, p = density of fluid, and y1 & y2 are = two heights about surface. Or is there another way?
     
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  3. Oct 4, 2004 #2

    arildno

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    1.By Benoulli, you find the velocity by which the fluid leaves the container (Torricellis law).
    2. Use projectile motion to determine R (you'll need to know how high above the ground the hole is)
     
  4. Oct 4, 2004 #3
    If v = (2gh)^1/2, then we turn to use the kinematic equations. y = H(height from top water level to floor)-h(height of top water level to hole in side of container), we know g, all we're missing is the original velocity, time, and acceleration. Is there something I'm missing?
     
  5. Oct 5, 2004 #4
    Your not missing anything. If you have the velocity, the rest is just simple kinematics.
     
  6. Oct 5, 2004 #5
    I get R = ((2gh)^(1/2))*t, is this correct?
     
  7. Oct 6, 2004 #6

    arildno

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    As long as "t" is the time it takes to reach the ground, yes.
     
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