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Little(?) problem

  1. May 1, 2010 #1
    Hi everyone,

    I’m studying the correction of an exercise and I there are some points I can’t see:
    In this exercise, we introduce a irrational x and function f so that f(kx)=kx-[kx] with k an integer included in the interval [0,N].

    It is said that f has N+1 values (Ok) that are included in the intervals [i/N,(i+1)/N] for i integers included in [0,N-1]… I can’t see this last point. If anyone could help me understand this point…

    Thanks in advance!
  2. jcsd
  3. May 1, 2010 #2
    [itex]y-[y]\in [0,1][/itex]
    [itex]\cup\{[i/N,i+1/N]:i\in \mathbb{Z}\cap [0,N-1]\}=[0,1][/itex].
    Is it saying anything more than that?
  4. May 2, 2010 #3
    Nothing else, they just say that for each k integer included in [0,N], x an irrational, there exists an i integer included in [0,N-1] so that f(kx) is included in the interval [i/N,(i+1)/N] (and then, for the rest of the exercise, since there are N+1 values and N intervals, there are two values included in the same [i/N,(i+1)/N]).

    But I don't know why f(kx) is included in [i/N,(i+1)/N]...
  5. May 2, 2010 #4
    It's not saying f(kx) is included in any particular [i/N,(i+1)/N], only that it's somewhere in [0,1] and since the sets [i/N,(i+1)/N] cover the whole of [0,1] it's got to be in one of them.
  6. May 2, 2010 #5
    Ok Martin I got it. (In fact, the important in this exercise is that there exists two values k1 and k2 so that abs(f(k1x)-f(k2x))<=1/N.)

    Thanks very much!!
  7. May 2, 2010 #6
    Yes I guessed that. Glad to be of help.
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