- #1

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**ln(-1) = 0 ???!**

supposed that we have

[tex] \ln(-1) [/tex]

then

[tex] \frac{2}{2}\ln(-1) [/tex]

so

[tex] \frac{1}{2}\ln(-1)^2 [/tex]

this is equal to

[tex] \frac{1}{2}\ln(1) [/tex]

and if this is equal to 0 the we can say that

[tex] ln(-1) = 0 [/tex]

is this right , wrong, are there any explanations for this?