(adsbygoogle = window.adsbygoogle || []).push({}); ln(-1) = 0 ???!

supposed that we have

[tex] \ln(-1) [/tex]

then

[tex] \frac{2}{2}\ln(-1) [/tex]

so

[tex] \frac{1}{2}\ln(-1)^2 [/tex]

this is equal to

[tex] \frac{1}{2}\ln(1) [/tex]

and if this is equal to 0 the we can say that

[tex] ln(-1) = 0 [/tex]

is this right , wrong, are there any explanations for this?

**Physics Forums - The Fusion of Science and Community**

# Ln(-1) = 0 ?!

Know someone interested in this topic? Share a link to this question via email,
Google+,
Twitter, or
Facebook

- Similar discussions for: Ln(-1) = 0 ?!

Loading...

**Physics Forums - The Fusion of Science and Community**