# Ln limit result question

1. Feb 12, 2009

### transgalactic

$$\lim_{x->3^-} ln^2(9-x^2)=+\infty$$
the meaning of this ln is e^+infinity=closser to 0

how is that??

by my math e^+infinity is infinity

2. Feb 12, 2009

### JG89

As x approaches three, then ln(9 - x^2) approaches 0 and so the value goes to negative infinity, squaring it gives you positive infinity.

3. Feb 12, 2009

### Staff: Mentor

Not quite. As x approaches 3 from below, 9 - x^2 approaches 0, from the positive side, so ln(9 -x^2) approaches negative infinity, so [ln(9 - x^2)]^2 approaches positive infinity.

4. Feb 12, 2009

### JG89

Oops, I meant to say that the value within the ln approaches 0 and so ln approaches negative infinity, which when squared is positive infinity.

5. Feb 12, 2009

### Staff: Mentor

Happens to the best of us