Calculating Horsepower from 100 kgs Load on 10cm Axle with 3 Arms

[kalpesh]

Please let me know the equation to calculate the following

i have a mass of 100 kgs

i have an axel of 10cms diameter connected by 3 arms 120 degrees apart.

the length of the arm is 100cms

i want to know that if the load is dropped from above, that is when the arm reaches on the top where it collects the load of 100 kgs and falls freely.

What is the load it will create on the axel which i want to use for rotating a generator.

I want to know the horsepowers that will be generated as i got a generator which requires 500 horsepower engines.

I have the liberty of a loat of load on the top, which is not expected to get exhausted. please help

kalpesh

 

[Aaron Barnard]

Unfortunately, there is no equation that can answer this question as it is impossible to calculate the exact load on the axle without knowing the exact properties of the generator, such as the size and type of the generator and the amount of energy it will take to turn it. However, you can use some rough estimates to get an idea of the load it can create. For example, if you assume that the weight of the generator is negligible compared to the load of 100 kgs, then you can use the following equation to calculate the load on the axle:

Load = (100 kgs * 10 cm) / 3 arms * 120 degrees

This equation will give you an approximate value for the load on the axle when the arm reaches the top with the load of 100 kgs. From this, you can estimate the horsepower generated by the generator.

 

[GSXR750]

To calculate the horsepower generated by the load of 100 kgs on a 10cm axle with 3 arms, we first need to determine the force exerted by the load on the axle. This can be calculated using the equation F = mg, where F is the force in Newtons, m is the mass in kilograms, and g is the acceleration due to gravity (9.8 m/s^2). In this case, the force exerted by the load is 100 x 9.8 = 980 Newtons.

Next, we need to calculate the torque exerted by the load on the axle. Torque is defined as the force multiplied by the distance from the pivot point. In this case, the pivot point is the center of the axle and the distance from the pivot point is the length of the arm, which is 100cm or 1 meter. Therefore, the torque can be calculated as 980 x 1 = 980 Nm.

To convert this torque into horsepower, we can use the equation HP = (T x RPM) / 5252, where HP is horsepower, T is torque in pound-feet, and RPM is the rotational speed in revolutions per minute. Since we already have torque in Newton-meters, we need to convert it to pound-feet by dividing by 0.7376. This gives us a torque of 980 / 0.7376 = 1328.4 pound-feet.

Now, we need to determine the rotational speed of the axle. Since the load is dropped from above and falls freely, we can use the equation v = sqrt(2gh), where v is the velocity, g is the acceleration due to gravity, and h is the height from which the load is dropped. In this case, h is equal to the length of the arm, which is 100cm or 1 meter. Therefore, the velocity of the load when it reaches the bottom is v = sqrt(2 x 9.8 x 1) = 4.427 m/s.

To determine the rotational speed, we need to convert this velocity into revolutions per minute. The circumference of the axle can be calculated as 2 x pi x radius, which is 2 x 3.14 x 5cm = 31.4 cm or 0.314 m. Therefore, the number of revolutions per minute is equal to the velocity divided by the circumference, which