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Local linearization

  1. Nov 1, 2009 #1
    f(x) = cosx, a = [tex]\pi[/tex]/2
    since, L(x)=f'(x)(x-a) -f(a)
    f'(x) = -sinx
    = -sin([tex]\pi[/tex]/2)(x-[tex]\pi[/tex]/2) - f(a)


    I'm stuck as to where to go next, is this even right?
     
  2. jcsd
  3. Nov 1, 2009 #2
    Nevermind, I got it to be -x+[tex]\pi[/tex]/2, which is correct!
     
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