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## Main Question or Discussion Point

for the equation... y = x^3 - 2x^2 -5x +2

is its local minima at (2.120,-8.061)

Thanks

is its local minima at (2.120,-8.061)

Thanks

- Thread starter daniel69
- Start date

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for the equation... y = x^3 - 2x^2 -5x +2

is its local minima at (2.120,-8.061)

Thanks

is its local minima at (2.120,-8.061)

Thanks

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1.f'(x)=0

2.f'(x) does not exist

since your function is a polynomial it means that also it's derivative will be a polynomial of a less degrees, so it will be defined for all real numbers.

Now, after you find the cr. points, how do you distinguish whether it is a local minima or a local maxima?

SInce it is a cubic polynomial there will be max two local extremes.

Say c,d are such cr. points

then c is said to be a local minima if: let e>0, such that e-->0

so f'(c-e)<0,and f'(c+e)>0

and d i said to be a local max, if

f'(d-e)>0 and f'(d+e)<0.

Now do it in particular for your function.

Can you go from here???

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i just look at the hessian to figure out if it's a min or not

tiny-tim

Science Advisor

Homework Helper

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Hi daniel69!

How did you get x = 2.120 ?

How did you get x = 2.120 ?

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Look at what?i just look at the hessian to figure out if it's a min or not

HallsofIvy

Science Advisor

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Since this is a function of a single variable, its "Hessian" is just its second derivative. However, that would be assuming that the x value given really does give either a maximum or a minimum- which, I think, was part of the question.i just look at the hessian to figure out if it's a min or not

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