Can a State with Nonmeasurable Local Properties be Described by Quantum Rules?

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In summary, the conversation discusses the state of a spin 1 boson and a spin 1/2 particle, which is a mixture of two different states. The question arises whether this state is locally measurable. It is suggested to consider the state as a global 6x1 vector and apply usual quantum rules. However, the notation used is unfamiliar and a source is requested for clarification.
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If the state considered is :##\frac{1}{\sqrt{2}}\left[\left(\begin{array}{c}1\\0\\0\end{array}\right)\left(\begin{array}{c}0\\1\end{array}\right)-\left(\begin{array}{c}1\\0 \end{array}\right)\left(\begin{array}{c}0\\0\\1\end{array}\right)\right]##

It seems to me it were not locally measurable since it is a mixture of spin 1 boson with a spin 1/2 ?

However how about considering as a global 6x1 vector and apply usual quantum rules, would it make any sense ?
 
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This notation is totally unknown to me. Could you explain, what you mean by your symbols?
 
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A citation of your source might help, too.
 
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1. What are locally nonmeasurable states?

Locally nonmeasurable states refer to quantum states that cannot be measured by a local observable. This means that the state does not have a definite value for a particular observable at a specific point in space.

2. How are locally nonmeasurable states different from measurable states?

Measurable states have a definite value for a specific observable at a particular point in space. Locally nonmeasurable states, on the other hand, do not have a definite value for a specific observable at a particular point in space.

3. What is the significance of locally nonmeasurable states?

Locally nonmeasurable states play an important role in quantum mechanics as they demonstrate the limitations of the classical notion of a state having a definite value for a specific observable at a particular point in space. They also have implications for quantum entanglement and non-locality.

4. How are locally nonmeasurable states measured?

Locally nonmeasurable states cannot be measured directly using a single observable. Instead, they can be indirectly measured through correlations with other states or through the use of entanglement and quantum teleportation.

5. Can locally nonmeasurable states be observed in the real world?

Yes, locally nonmeasurable states have been observed in experiments, particularly in the study of quantum entanglement. However, their effects are often subtle and require advanced measurement techniques to detect.

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