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yourmom98
- 42
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is the locus of points equidistant from the two given points on the same line as the perpendicular bisector of the 2 points?
If the answer to (a) is a vertical line why isn't the answer to (b) a circle?yourmom98 said:a) the diagram would be a vertical line
b) the diagram would be a sinusoidal function
Two parabolas (in 2D)? A cylinder (in 3D)?c) a parabola
I guess you meant a parallel line.d) horizontal line
You can only give an equation if you have an equation to begin with. If the question didn't give you an equation, do you really want to be the one who starts it?am i supposed to give an equation?
Let a = (0,-2) and b = (0,2); and c = (x,y) is such a point that d(a,c) + d(b,c) = 8 where d is the (Euclidian) distance function. For any two points u = (u1,u2) and v = (v1,v2), d is defined as d(u,v) = [itex]\sqrt{(v_1-u_1)^2+(v_2-u_2)^2}[/itex]. So the locus that the question is asking is "the set of all (x,y) points in [itex]\mathbb R^2[/itex] such that [itex]\sqrt{(x-0)^2+(y+2)^2}[/itex] + [itex]\sqrt{(x-0)^2+(y-2)^2} = 8.[/itex]"how would i find the equation of this locus where point such that the sum of whoose distances from (0,-2) and (0,2) is 8 cause. well its not that i CANT find the equation its just that i have to draw and ellipse to figure it out i wonder if there is an more accuate way? so far my answer is 16=x^2+y^2 is this rite?
A perpendicular bisector is a line, segment, or ray that divides a line segment into two equal parts at a right angle.
To find the equation of a perpendicular bisector, you will need to determine the slope of the original line and then find the negative reciprocal of that slope. This new slope will be used to create the equation of the perpendicular bisector, along with the midpoint of the original line segment.
The perpendicular bisector theorem states that if a point is equidistant from the endpoints of a line segment, then that point lies on the perpendicular bisector of that line segment. This theorem can be used to find the equation of the perpendicular bisector or to determine if a point lies on the bisector.
Yes, a perpendicular bisector can be a line segment, as long as it divides the original line segment into two equal parts and forms a right angle at the midpoint.
The perpendicular bisector is used in geometry to construct right angles, bisect line segments, and create perpendicular lines. It is also used in proofs and constructions to show the relationship between angles and lines.