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I know that logarithms to the base 1 is undefined, due to the reason that:

[itex]\log_1{x} = \frac{\log_a{x}}{\log_a{1}}[/itex]

And this leads to divison by zero, which is undefined.

There was a question in one of my textbooks that asked describe the graph that results if [itex]y = \log_1{x}[/itex]. Is such a graph even possible?

If I switch this logarithm to exponential form I would get:

[itex]1^y = x[/itex]

Now, is it possible that the graph could be y = 1 and x = 1? Since [itex]1^y = x^1[/itex], [itex]y = 1[/itex] and [itex]x = 1[/itex].

Or is it the point of intersection of these two lines? If not, what is it?

Thanks.

[itex]\log_1{x} = \frac{\log_a{x}}{\log_a{1}}[/itex]

And this leads to divison by zero, which is undefined.

There was a question in one of my textbooks that asked describe the graph that results if [itex]y = \log_1{x}[/itex]. Is such a graph even possible?

If I switch this logarithm to exponential form I would get:

[itex]1^y = x[/itex]

Now, is it possible that the graph could be y = 1 and x = 1? Since [itex]1^y = x^1[/itex], [itex]y = 1[/itex] and [itex]x = 1[/itex].

Or is it the point of intersection of these two lines? If not, what is it?

Thanks.

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