# Log equations

1. Apr 23, 2007

### Corkery

1. The problem statement, all variables and given/known data

solve:Log(subscript 5) X = 1/2log(subscript 5) 25

2. Relevant equations

3. The attempt at a solution[/
Log(subscript 5) X = 1/2log(subscript 5) 25
--------------- ---------------------
Log(subscript 5) Log(subscript 5)

Then they cancel out and I got X = 1/2Log(subscript 5) 25
-----------------------
Log(subscript 5)

It looks wierd but i hope you understand what i'm trying to show you.

2. Apr 23, 2007

### siddharthmishra19

It doesn't work that way!!

$$log_5 x = (1/2)(log_5 25)$$
$$log_5 x = (1/2) 2$$
$$log_5 x = 1$$

Please learn the basics and stuff... it will help!

3. Apr 23, 2007

### HallsofIvy

Staff Emeritus
I would have done it a slightly different way:
$$log_5(X)= \frac{1}{2}log_5(25)$$
$$log_5(X)= log_5(25^{\frac{1}{2}})$$
$$log_5(X)= log_5(5)$$
Now it should be easy to see what X is.

4. Apr 23, 2007

### Corkery

Learn the basics yourself, you got it wrong!!!!!! jk

5. Apr 24, 2007

### HallsofIvy

Staff Emeritus
No, while his statement about learning the basics is a little harsh (though true), his calculation is exactly correct. log5(25)= 2 so (1/2)log5(25)= 1. log5(x)= 1 so x= 1.

You may need to review yourself!

6. Apr 24, 2007

### Corkery

well in that case im really sorry! But its not like i meant it in a hatefl way. Sorry once again.

7. Apr 24, 2007

### HallsofIvy

Staff Emeritus
I didn't think you did. But be careful, in the future, about telling someone else he is wrong. Especially without explaining exactly HOW it is wrong!

I've started, many times, to tell someone he was wrong, and while writing out exactly WHY he was wrong said "oops" and kept my mouth shut!

8. Apr 24, 2007

### drpizza

Speaking of "oops", I'm sure you meant x=5 (as you had a couple posts before.)