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jai6638
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Hey... requested my professor to give me a few word problems to enable me to improve my skills... am having problems solving them however and was hoping that you could guys could help me:
Q1) Use a calculator to evaluate the following powers. Round the results to five decimal placeS. Each of these powers has a rational exponent. Explain how you can use these powers to define 3^( sqrt of 2 ) which has an irrational exponent.
3^(14/10) = 4.65554
3^(141/100)=4.70697
3^(1414/10000)= 4.72770
3^(14142/10000)= 4.72873
3^(141421/100000)= 4.72878
3^(1414213/1000000)= 4.72880
3^( sqrt of 2 ) = 4.728804
so basically the value of 3^(sqrt of 2 ) comes after 3^(1414213/1000000)... hence, you could find the log of 3^14/10 which is .6679697566, then probably do the following : 3^(.667..+.667...+.667...+.667.. +.667 +.667.. +.667).
EDIT: damn .. what i did above doesn't make sense.. I am soo confused.! i do know that i can somehow use logs by finding the log of one value and then adding the solution multiple times to find the value of 3^ ( sqrt of 2 )
_________________________________________________________
Question 2:
Find a value of n for which (1+1/n)^n gives the value of e correct to 9 decimal places. Explain the process you used to find your answer.
log 2.718281828 = log ( 1+1/n)^n
log 2.718281828= n log ( 1+1/n)
log 2.718281828/ log (1+1/n ) = n
would that be the final answer?
thanks
Q1) Use a calculator to evaluate the following powers. Round the results to five decimal placeS. Each of these powers has a rational exponent. Explain how you can use these powers to define 3^( sqrt of 2 ) which has an irrational exponent.
3^(14/10) = 4.65554
3^(141/100)=4.70697
3^(1414/10000)= 4.72770
3^(14142/10000)= 4.72873
3^(141421/100000)= 4.72878
3^(1414213/1000000)= 4.72880
3^( sqrt of 2 ) = 4.728804
so basically the value of 3^(sqrt of 2 ) comes after 3^(1414213/1000000)... hence, you could find the log of 3^14/10 which is .6679697566, then probably do the following : 3^(.667..+.667...+.667...+.667.. +.667 +.667.. +.667).
EDIT: damn .. what i did above doesn't make sense.. I am soo confused.! i do know that i can somehow use logs by finding the log of one value and then adding the solution multiple times to find the value of 3^ ( sqrt of 2 )
_________________________________________________________
Question 2:
Find a value of n for which (1+1/n)^n gives the value of e correct to 9 decimal places. Explain the process you used to find your answer.
log 2.718281828 = log ( 1+1/n)^n
log 2.718281828= n log ( 1+1/n)
log 2.718281828/ log (1+1/n ) = n
would that be the final answer?
thanks
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