Log-linear Analysis

  • Thread starter AlexC
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  • #1
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I need to graph a relationship that is the combination of 2 exponential functions on log-linear graph paper.

I have: V = Cexp(-t/B) + Aexp(-t/S)

If it were simply V = Cexp(-t/B) then this wouldnt be a problem (by graphing log(V) = (-1/B)log(e)t + log(C) ) but I need to determine both the B and S parameters (possibly from the same graph). How can i do this?
 
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Answers and Replies

  • #2
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If t=ln(s), then V is linear in s...

Plot V vs. s.
 

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