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Log Overflow Problem

  1. Nov 30, 2009 #1
    "If your calculator has overflow issues with this problem, you can use this identity to solve for K:

    if log(K) = x + y then K = 10x * 10y

    Problem:

    log(K) = 127.702

    K = 5.04316 * 10127
    "



    Doesn't K = 10127 ?

    Where are they getting the 5.04316 from? How are they using that specified identity?
     
  2. jcsd
  3. Dec 1, 2009 #2

    Mark44

    Staff: Mentor

    log(K) = 127 + .702, so K = 10127 + .702= ?

    Now use the properties of exponents.
     
  4. Dec 1, 2009 #3

    HallsofIvy

    User Avatar
    Staff Emeritus
    Science Advisor

    If log(K)= 127.702 then K is NOT 10127 because K is NOT 127. You just said "log(K)= x+ y then K= 10x10y. 127.702= 172+ .702 so K= 1012710.702. And 10.702= 5.035006. (but not 5.04315- that would be closer to .703.)
     
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