# Log Problem

1. Apr 24, 2006

### ohlhauc1

Here is a problem that I was presented in my math class using logs and my entire group is stumped:

Peter deposits $800 into an investment fund that earns 8% per year, compounded annually. Mary Jane deposits$1000 into an investment fund that earns 6% per year, compounded annually? When will their investments be equal?

This is what we have so far:

800(1.08)^x = 1000(1.06)^x
0.8(1.08)^x = 1.06^x

log1.08(800) = x
log1.06(1000) = x

log1.08(800) = log1.06(1000)
log800/log1.08 = log1000/log1.06 (This does not work; they are not equal)

2. Apr 24, 2006

### dav2008

How exactly did you get from your second to third/fourth lines?

3. Apr 24, 2006

### NateTG

You made some sort of strange jump from:
$$0.8 \times 1.08^x= 1.06^x$$
to
$$log_{1.08}800=x$$

Perhaps you could try something else from
$$0.8 \times 1.08^x= 1.06^x$$
like dividing both sides by $1.08^x$

4. Apr 24, 2006

### ohlhauc1

Thanks for the help, but I just saw my major mistake. Here are my corrections:

(800)(1.08)^x = (1000)(1.06)^x
(1.08)^x = 1.25(1.06)^x
(1.08/1.06)^x = 1.25
(1.0189)^x = 1.25
xlog(1.0189)^x = log1.25 [Note: The bases are 10]
x = log1.25/log1.0189
x = 11.9
----> 12