- #1
yoleven
- 78
- 1
Homework Statement
A professor is doing a problem on the black board and ends up with the expression
[tex]\frac{Log A}{Log B}[/tex] = [tex]\frac{2}{3}[/tex]
.
He absentmindedly cancels the “log”, making the left-hand side A/B. (A very wrong thing to do!)
Luckily, he ends up with the correct values for A and B. What are these values?
The Attempt at a Solution
I wasn't sure what to do here. I figured 2/3 is .667
from the question I have Log A- Log B= .667
I set A to be equal to 10 which gives me a value of 1, then Log B would equal .333 because 1-.667 =.333
raising both sides to be powers of ten, I get B= 10.333
which is 2.15
This works except if the proffessor "cancelled the Log) Then 10/2.15 obviously isn't 2/3.
What should I do here?