Logarithmic Function with Vertical Asymtote at X=-6, Y Intercept=5

[merikukri]

what will be the logarithmic function with a vertical asymtote at X = -6 that has the intercept Y = 5

I know the denominator will be x+6 to get vertical asymtote, but don't know how to get Log Function ??

 

[Fermat]

There is no denominator. What does a log function look like ?

You log function will be of the form,

y = Alog(X+B)

Now you have to figure out values for A and B.

 

[merikukri]

There is no denominator. What does a log function look like ?
You log function will be of the form,
y = Alog(X+B)
Now you have to figure out values for A and B.

thanks for help, can you explain it in more details..I didn't understand the above function.

Regards

 

[merikukri]

There is no denominator. What does a log function look like ?
You log function will be of the form,
y = Alog(X+B)
Now you have to figure out values for A and B.

so its going to be something like L(x) : ( | X+6 |, sqrt 6 ) :uhh:

 

[Fermat]

It will be,

y = Alog((x+6)

so you got the B correct.

There is a y-intecept of 5, so

5 = Alog(0+6)

What is A ?

 

[merikukri]

It will be,
y = Alog((x+6)
so you got the B correct.
There is a y-intecept of 5, so
5 = Alog(0+6)
What is A ?

A is 5

 

[Fermat]

Nope.

5 = A.log(0+6)
A = 5/log(6)
A = 6.4254 (if taking logs to the base 10)
A = 2.7906 (if taking logs to the base e)