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Log Question !

  1. Nov 7, 2005 #1
    what will be the logarithmic function with a vertical asymtote at X = -6 that has the intercept Y = 5

    I know the denominator will be x+6 to get vertical asymtote, but don't know how to get Log Function ??
     
  2. jcsd
  3. Nov 7, 2005 #2

    Fermat

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    There is no denominator. What does a log function look like ?

    You log function will be of the form,

    y = Alog(X+B)

    Now you have to figure out values for A and B.
     
  4. Nov 7, 2005 #3
    thanks for help, can you explain it in more details..I didn't understand the above function.

    Regards
     
  5. Nov 7, 2005 #4
    so its going to be something like L(x) : ( | X+6 |, sqrt 6 ) :uhh:
     
  6. Nov 7, 2005 #5

    Fermat

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    It will be,

    y = Alog((x+6)

    so you got the B correct.

    There is a y-intecept of 5, so

    5 = Alog(0+6)

    What is A ?
     
  7. Nov 7, 2005 #6
    A is 5:frown:
     
  8. Nov 8, 2005 #7

    Fermat

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    Nope.

    5 = A.log(0+6)
    A = 5/log(6)
    A = 6.4254 (if taking logs to the base 10)
    A = 2.7906 (if taking logs to the base e)
     
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