- #1
Matt1234
- 142
- 0
Here is what the graph looks like on a graphing calculator (notice the equation at the top):
http://img62.imageshack.us/img62/8898/graphingcalc.jpg
Here is what my graph looks like:
http://img53.imageshack.us/img53/7475/lastscanc.jpg
I don't understand why the asymptote is shifted 6 units left instead of 3 units left, And the point on my graph don't seem quite right.
i have the points (-1, -3)
Yet the graphing calculator has (-1, -3.79)
Note : where i wrote original points I am referring to y = log x
I don't see what i hsve done wrong, can someone help me.
Thanks.
http://img62.imageshack.us/img62/8898/graphingcalc.jpg
Here is what my graph looks like:
http://img53.imageshack.us/img53/7475/lastscanc.jpg
I don't understand why the asymptote is shifted 6 units left instead of 3 units left, And the point on my graph don't seem quite right.
i have the points (-1, -3)
Yet the graphing calculator has (-1, -3.79)
Note : where i wrote original points I am referring to y = log x
I don't see what i hsve done wrong, can someone help me.
Thanks.
Last edited by a moderator: