# Logarithm Help

1. Oct 22, 2011

### Jemal

I'm trying to teach myself logs for a statistics quiz... I know this is probably easy but i never really learned logs.

1. The problem statement, all variables and given/known data
I have to take the logarithm of both side of y=.70 + .59x

2. Relevant equations
n/a

3. The attempt at a solution

y=.70+.59x

So i get Logy= Log.70 + Log (.59x)
Logy = -.1549 + log.59x

I dont know what to do with the log(.59x) Can i separate the .59 and the x somehow?

2. Oct 22, 2011

### gb7nash

No. You can't do this. We only know that log(ab) = log(a) + log(b). The correct equation is:

Log(y) = Log(.70+.59x)

What is it you're trying to do?

3. Oct 22, 2011

### Jemal

I just need to take the log of both sides and simplify.

So I get log(y) = log(.70+.59x)

I cant seem to find any laws of logs that lets me simplify log(.70+.59x)

Is that how the equation can be left?

4. Oct 22, 2011

### gb7nash

Pretty much. There's not much else you can do with that equation.

5. Oct 22, 2011

### Jemal

ok thanks a bunch

6. Oct 22, 2011

### Staff: Mentor

Why do you think you need to do this? What's the context from which this arises?