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Logarithm Inequality

  1. Sep 22, 2013 #1
    Log x ((x+3)/(x-1) > Log x x ??

    I've managed to find 4 conditions for this inequality:
    1. -1 > x > 3
    2. x > -3
    3. x > 0
    4. x ≠ 1

    but I'm not sure how to write the solution. Is it " 0 < x & 1 < 0 < 3 " ?

    Thanks.
     
  2. jcsd
  3. Sep 22, 2013 #2

    Office_Shredder

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    I think you mistyped what this is supposed to be.

    If you have multiple conditions, just write them out the way you would state them in English. For example, if I asked for the solutions to |x|>1 I would write "x>1 or x<-1". If someone asked for the solutions to |x2-4| > 1, I would write " x>sqrt(5) or -sqrt(3)<x<sqrt(3) or x<-sqrt(5)".

    Notice you will never have an and condition. If you wrote something like " 1<x<5 and 2<x<7" you should just replace that with "2<x<5". If you have two conditions that are incompatible, just say there are no solutions rather than writing something like "1<x<3 and 5<x<6"
     
  4. Sep 22, 2013 #3

    Hi. Thank you for the reply.

    Could you help me to find x that would satisfy the inequality?
     
  5. Sep 22, 2013 #4

    Office_Shredder

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    If you want help solving a homework or homework-style question, you should post in the homework forum and follow the template there. Most importantly make sure to show what work you have attempted already in your post.
     
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