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Logarithm notation question

  1. Jul 19, 2012 #1
    1. The problem statement, all variables and given/known data

    I've never seen a number above the ln like that, usually it's on another term or simply ln(2). What does that numer mean? Is it Log(e)^2 i.e. (Loge)(Loge)? That doesn't make any sense to me.
    2. Relevant equations

    3. The attempt at a solution

    Bring the 2 down and divide both sides by it.
    ln (1+x)=2

    (e^2) - 1=x

    It's supposed to have one more solution, x = (1/(e^2)) - 1
  2. jcsd
  3. Jul 19, 2012 #2


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    It means

  4. Jul 19, 2012 #3
    Ah that makes complete sense. Thank you.
  5. Jul 20, 2012 #4


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    Remember that for, any function, f, the notation "f(x)" means the function evaluated at x- that is, f(x) is a number and so [itex]f^n(x)[/itex] is that number to the nth power. Generally, for any function, f, the notation fn means "the value of f to the nth power".

    The only (unfortunate) exception to that is '-1'. [itex]f^{-1}[/itex] typically means "the inverse function", not 1/f.
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