1. Limited time only! Sign up for a free 30min personal tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Homework Help: Logarithm overkill!

  1. Jan 23, 2008 #1
    [SOLVED] Logarithm overkill!

    Hello again!
    I have been working on this log, and the longer I work on it, the more confused I get! Here's the problem:
    Find the exact value for:


    Here's what I've tried so far:


    [tex]e^{x} = ln(e^{e^5}}) [/tex]
    [tex]e^{x} = e^{e^5}}[/tex]
    [tex]e^{5} = (2.72)^{5}[/tex]
    [tex]e^{x} = e^{149}[/tex]
    [tex]x = 149 [/tex]

    ....I have no idea if I'm doing this right, but I'm not feeling like I am...Help?
  2. jcsd
  3. Jan 23, 2008 #2


    User Avatar
    Homework Helper

    are you trying to do two logs then two e's or one e then a log then two e's
    very confusing!
  4. Jan 23, 2008 #3
    You have to use one of the properties of logs. When the bases of the exponent and log are same, they cancel.
  5. Jan 23, 2008 #4

    Shooting Star

    User Avatar
    Homework Helper

    Hint: the answer is an integer.
  6. Feb 3, 2008 #5
    ln e ^x =x
    Can you take it from there?
  7. Feb 3, 2008 #6
    i think the answer is 5 since ln and e cancaled out!
  8. Feb 3, 2008 #7
    hey thanks everyone! i was able to figure it out from there you guys are always a big help :)
  9. Feb 9, 2008 #8
    This is true
  10. Feb 9, 2008 #9


    User Avatar
    Science Advisor
    Homework Helper

    NEVER post the answer just like that!
  11. Feb 9, 2008 #10
    haha, I guess a perfect hint would be

    [tex] lne^x=x[/tex]
Share this great discussion with others via Reddit, Google+, Twitter, or Facebook