1. Not finding help here? Sign up for a free 30min tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Logarithm problem

  1. Oct 5, 2006 #1
    log2 2x -log3 (3x-1) = 2, solve for x....

    you guys dont hv 2 solve the question for me, just guide me to the answer:smile:
  2. jcsd
  3. Oct 5, 2006 #2


    User Avatar
    Science Advisor
    Homework Helper
    Gold Member
    Dearly Missed

    First step:
    Convert one logarithm into its equivalent logarithm expression for the other base.
    To do so, the general picture is that for positive number a,b,c, we have:
    Taking the a-logarithm of the middle and last expression, we have:
    That is:
  4. Oct 6, 2006 #3
    ok ive done the 1st step by changing log2 2x to (log3 2x)/(log3 2)

    (log3 2x)/(log3 2) - log3 (3x-1) = 2

    1.585(log3 2x) -log3 (3x-1) = 2

    log3 (2x)^1.585 - log3 (3x-1) = 2

    log3 ( (2x^1.585)/(3x-1) ) = 2 , is this correct? then what?
  5. Oct 6, 2006 #4
    ok i went ahead & solve the equation to get x=0.522....but when i substitute x=0.522 into the initial equation i did not get 2...what hv i done wrong?
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook

Have something to add?

Similar Discussions: Logarithm problem
  1. Logarithm Problem (Replies: 3)

  2. Logarithm problem (Replies: 16)

  3. Logarithmic problem (Replies: 18)

  4. Logarithmic Problem (Replies: 4)