Logarithm Problem

  • Thread starter math4life
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  • #1
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Homework Statement


1) Solve the equation using the exponential form of the equation.

Log2(2-5x)=7

2) Rewrite as a single logarithmic expression:

3log x +(1/2)log z



Homework Equations





The Attempt at a Solution



1) I have no idea how to solve this.

2) I know that two logarithms multiply to add, but these have different bases so I do not know what to do.

Thanks.
 
Last edited:

Answers and Replies

  • #2
rock.freak667
Homework Helper
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Log2(2-5x)=7

Here is a hint.

[tex]a^b =c \Rightarrow b= log_a c[/tex]

2) Rewrite as a single logarithmic expression:

3log x +(1/2)log z

they are in the same base. Logx usually means log10x.

Use the rule

[tex]rlog_a x = log_a x^2[/tex]
 
  • #3
Mentallic
Homework Helper
3,798
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I'll just fix up rock.freak667's little typo there.

What was meant to be said is: [tex]r.log_a(x)=log_a(x^r)[/tex]

Coupled with the rule that [tex]log_a(b)+log_a(c)=log_a(bc)[/tex]

You should have no problem solving the second one :smile:
 
  • #4
35,428
7,289
I think it might be helpful to add that a logarithm can be thought of as the exponent on the base (the number raised to a power) that results in a particular number. So for example, log10100 means the exponent on 10 that results in 100. In other words, this logarithm is the answer to the question 10? = 100. Pretty clearly, the placeholder represented by ? is 2.

Every equation of the form logbx = y can be rewritten as an equivalent exponential equation by = x, and vice versa, with the only restrictions being that b > 0, and b[itex]\neq[/itex] 1, and x > 0.
 

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