y = (sin2x)(adsbygoogle = window.adsbygoogle || []).push({}); ^{3}(x^{4}-4x)^{6}divided by (cosx) + e^{3x}

i came out with an answer

y' = (sin2x)^{3}(x^{4}-4x)^{6}divided by (cosx) + e^{3x}[3cot2x + 24x^{3}-24 divided by x^{4}-4x + Tanx + 3x

could someone tell me if im right?

i dont know if this is what im supose to do,

if you want me to write out exactly what i did i can.

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# Logarithmic Differentiation

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