- #1
ritwik06
- 580
- 0
Homework Statement
[tex]x=\frac{1+\frac{f(x+1)}{1!}+\frac{f^{2}(x+1)}{2!}+\frac{f^{3}(x+1)}{3!}+...}{1+\frac{f(x)}{1!}+\frac{f^{2}(x)}{2!}+\frac{f^{3}(x)}{3!}+...}[/tex]
f(x) is a twice differentaible equation.
1. Find the possible values of x when;
f(x+0.5)<f(x-0.5)
2. Find the possible values of x when;
f(|x|+e-1)<f(|x|+e-2)+1
The Attempt at a Solution
On simplifying i get:
ln x= f(x+1)- f(x)
The only other data given is that f(x) is twice differentiable, which just means that when the function is expressed it will have two distinct constants, right? How shall I proceed?