- #1

- 76

- 0

solve for X..

im realy lost in this class i just came for one day and the teacher said just try the question using logarithms :S and i dont wahts going on...

this is what i did

4x-2x-6=0

2x-6=0

x=3...

but the answer is log2(3)

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- Thread starter Karma
- Start date

- #1

- 76

- 0

solve for X..

im realy lost in this class i just came for one day and the teacher said just try the question using logarithms :S and i dont wahts going on...

this is what i did

4x-2x-6=0

2x-6=0

x=3...

but the answer is log2(3)

- #2

- 382

- 2

Let 2^x = y.

Form a quadratic equation.

Solve the equation.

Substitute your answer back into 2^x = y.

Use logarithms to solve for x.

- #3

HallsofIvy

Science Advisor

Homework Helper

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Karma said:

solve for X..

im realy lost in this class i just came for one day and the teacher said just try the question using logarithms :S and i dont wahts going on...

this is what i did

4x-2x-6=0

2x-6=0

x=3...

but the answer is log2(3)

You "lost" the exponentials! 2

As Leong suggested, since 2

Now you know that y= 2

Of course 2

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