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Logarithms solving for x

  • Thread starter emma3001
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  • #1
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Solve the equation log2x + log4x= 5. To start, should I change this to an exponential.... I am stuck because I have only done log questions that have the same base.
 

Answers and Replies

  • #2
Dick
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Convert them to the same base log_a(x)=log_b(x)/log_b(a).
 
  • #3
HallsofIvy
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Solve the equation log2x + log4x= 5. To start, should I change this to an exponential.... I am stuck because I have only done log questions that have the same base.
What do you mean by "log2x+ log4x= 5"? I would interpret that as log(2x)+ log(4x)= 5 so log(6x)= 5 which is easy. If you mean "log_2(x)+ log_4(x)= 5" then use Dick's hint.
log_4(x)= log_2(x)/log_2(4)= ?
 
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  • #4
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Convert them to the same base log_a(x)=log_b(x)/log_b(a).
can u help solving a problem????
 
  • #5
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can u help solve a problem???
 
  • #6
Dick
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Can u post the problem? Under Forum Tools, "Post a New Thread". That's your first step.
 

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