- 45

- 0

**logarithms STUCK!!**

8logx-3logx^2 = log8x - log4x

im struggling to find x. my working out so far is:

rhs log8x-log4x

= log2

= 8logx - 3logx^2 = log 2

= 8logx - 3logx^2 - log 2 = 0

= -b+ or - the square root of b^2-4ac divided by 2a

a = -3 b = 8 c = - 2

= -8 + or - sqaure root of 8^2 (-4x-3x^2-2) divided by 2x - 3^2

x= -8 + or - square root of 64 - 24 divided by -6

= square of 40 divided by -6

= -8 + or - 6.3245 divided by -6

= - 8 + or - , -1.05408

x= -9.0540

x= 6.94592

can anyone help me. am stuck and cant see where ive gone wrong